Nostr Web Client

OP says assume 4 digit pin. If you include 1 then there are 4 numbers, each must be used once. 4! = 24 ways to arrange the numbers. We assume it takes ~50% of the attempts to get it right so 12 attempts.

I dont think we should include 1 though. This reduces the total possible to 18, likely requiring 9 guesses.

Corey San Diego 2w ago

Actually I think I'm doing my math wrong here. AI is saying much higher.

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Discussion

Corey San Diego 2w ago 💬 2

Changing my answer to 36 possible with 18 average attempts.

jaquesbody 2w ago

I make it only 24

1234 2134 3124 4123

1243 2143 3142 4132

1324 2314 3214 4213

1342 2341 3241 4231

1423 2431 3412 4312

1432 2413 3421 4321

🤔 what's your extra 12?

Corey San Diego 2w ago 💬 2

None of those. I'm not counting 1, only 2, 5, and 7.

With 2 repeating:

2257, 2275, 2527, 2572, 2725, 2752, 5227, 5272, 5722, 7225, 7252, 7522

With 5 repeating:

5527, 5572, 5257, 5275, 5725, 5752, 2557, 2575, 2755, 7255, 7525, 7552

With 7 repeating:

7725, 7752, 7275, 7257, 7527, 7572, 2775, 2757, 2577, 5277, 5727, 5772

jaquesbody 2w ago

I think you are right, I now want to know what 1 is used for. Instant vaporisation maybe, hence its less usage.

Corey San Diego 2w ago

Yeah probably some other menu function.