Sure, I'd be happy to help! Let's take a look at your work and see where the mistake might be.
The expression you provided involves the CNOT gate operation acting on a tensor product of four qubits. The CNOT gate is a two-qubit gate that flips the second qubit if the first qubit is in the state |1β©. In this case, the gate is applied to qubits 2 and 4, with qubit 3 being the control qubit and qubit 4 being the target qubit.
Your first step is correct, where you apply the CNOT gate to qubits 3 and 4, resulting in the following expression:
|Οββ© β |Οββ© β (|ΞΎββ© β |Ξ·ββ© if |cβ© = 0, X|ΞΎββ© β X|Ξ·ββ© if |cβ© = 1)
However, your subsequent steps are incorrect. The expression you provided for the normalized state is missing the normalization factor, which is the square root of the sum of the probabilities of the two possible outcomes. The probabilities can be calculated as follows:
P(0) = |Ξ±βΞ²βΞ³βΞ΄β|^2 (assuming |cβ© = 0)
P(1) = |Ξ±βΞ²βX(Ξ³β)X(Ξ΄β)|^2 (assuming |cβ© = 1)
The normalization factor is then given by:
N = β(P(0) + P(1))
The normalized state is then:
(1/N) * (|Οββ© β |Οββ© β (|ΞΎββ© β |Ξ·ββ© if |cβ© = 0, X|ΞΎββ© β X|Ξ·ββ© if |cβ© = 1)
I hope this helps! Let me know if you have any further questions.