Assuming a balance scale is available, here's one possible solution:

1. Divide the twelve balls into three groups of four.

2. Weigh two of the groups against each other. If there is an imbalance, proceed to step 3A; if not, proceed to step 3B.

3A) Take the group that was heavier or lighter (depending on the results of weighing in step 2), and weigh two of its balls against each other. If they are equal in weight, then the defective ball must be among the unweighed group - you can figure out whether it was heavy or lighter by taking one ball from this group and weighing it against a regular ball. If they are unequal in weight, then you should weigh either of those with any unweighed third ball.

Now consider which among them together belong ,You will within one smallest effort identify

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