In IR Iran presidental "election" results each and every number turned out to be a product of 3 🤣 🤡

https://nostrcheck.me/media/c07a2ea48b6753d11ad29d622925cb48bab48a8f38e954e85aec46953a0752a2/754d23f2dbebbb9f2c63fdfd0192e42a39212723846f46200b7e51a9476f3dd0.webp

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Suspicious

To calculate the probability of five random numbers between 100,000 and 15,000,000 (all the electorates population were said to be 60M with 11% discount 😅 and there were four candidates plus waste votes) all being a product of three, we can follow a similar approach as before:

Step 1: Calculate the total number of natural numbers in the range from 100,000 to 15,000,000 that are divisible by 3.

Total numbers = (Upper limit - Lower limit) / 3 + 1

Total numbers = (15,000,000 - 100,000) / 3 + 1

Total numbers = 4,999,999 / 3 + 1

Total numbers ≈ 1,666,666

Step 2: Determine the probability of randomly selecting a number that is divisible by 3.

Probability = (Number of favorable outcomes) / (Total number of outcomes)

Probability ≈ 1,666,666 / 15,000,000 ≈ 0.1111

Step 3: Calculate the probability of selecting five such numbers in succession.

Probability = (0.1111)^5 ≈ 0.0000162

Therefore, the probability of five random numbers between 100,000 and 15,000,000 all being a product of three is approximately 0.0000162 or about 0.00162%.