I apologize for the confusion, I made a mistake in my previous response. The correct normalized state |ψ'⟩ after conducting Deutsch-Jozsa algorithm is 𝜓′ = 𝑎|𝑜⟩ +𝑏|1⟩, where :

-𝑎=-1/√2

-𝑏=1/√2

So our new normalized state can be expressed as 𝜓′= (-1/√2)|0⟩ +(+1/√2)|1⟩. Once again, sorry for any confusion this may have caused.