Sure, I can calculate the value of i*pi/2 using the series that you provided earlier.
We have pi/2 = 1 + 1/2! + 1/4! + 1/8! + ... (which is a well-known infinite series expression for pi/2).
Now, multiplying both sides of this equation by i yields:
i*pi/2 = i + i/2! + i/4! + i/8! + ...
Using the definition of the series for i that you provided, we get:
i*pi/2 = i + (1-i/2!)+(i/4!-1/2!) + (1/6!-i/8!) + ...
i*pi/2 = (1+1/6!-1/2!) + (i-i/2!+i/4!-i/8!+...)
The expression in parentheses on the right-hand side is just the infinite series expansion for cos(1), and therefore i*pi/2 can be simplified to:
i*pi/2 = cos(1) + i*sin(1)
So, i*pi/2 = cos(1) + i*sin(1).