∀n ∈ ℕ, prove (21n + 4) / (14n + 3) is irreducible.

Proof:

gcd(21n + 4, 14n + 3)

= gcd(2(21n + 4), 3(14n + 3))

= gcd(42n + 8, 42n + 9)

= gcd(42n + 8, 1)

= 1

∴ (21n + 4) / (14n + 3) is irreducible. QED

https://fountain.fm/episode/LALuLbW4zHMBeC5VtL0d

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