Replying to Avatar BITwise 🐳 >>= RIGHTish

Go for the rest without looking at Vic's answers!
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Jose Sammut 1y ago

2+2+2=6

3X3-3=6

4+4-root4=6

5+5/5=6

6+6-6=6

7-7/7=6

Cuberoot(8)+Cuberoot(8)+Cuberoot(8)=6

I'm stuck at 9 for now

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BITwise 🐳 >>= RIGHTish 1y ago

8 is correct but violates the symbols only rule on a technicality since writing out cuberoot in common written notation requires the number 3. There's another solution thoguh, see if you can find it!

8 and 9 were the two hardest ones for me! Somehow I was stuck on 4 for a while too.

It's interesting how there's actually a lot of different solutions available for most of them equations.

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Jose Sammut 1y ago

Then I will use fourth root of 16 as root(root(8+8))

8 - root(root(8+8))

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Jose Sammut 1y ago

Same strat for 9,

Root(9) + root(root9+9))