Mathematically, if there are two or more mempools, the only way for there to be no second best is if all mempools are equal.
we’re not *the* mempool but we’re *the best* mempool. and there is no second best.
h/r nostr:npub1xtscya34g58tk0z605fvr788k263gsu6cy9x0mhnm87echrgufzsevkk5s
Mathematically, if there are two or more mempools, the only way for there to be no second best is if all mempools are equal.
