How many nsec can be created before they run out? Does anyone have the math on this?

#AskNostr

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Lol

25

69420

The answer is 2^256

If your answer is correct, that would be:

115 quattuorvigintillion 792 trevigintillion 89 duovigintillion 237 unvigintillion 316 vigintillion 195 novemdecillion 423 octodecillion 570 septendecillion 985 sexdecillion 8 quindecillion 687 quattuordecillion 907 tredecillion 853 duodecillion 269 undecillion 984 decillion 665 nonillion 640 octillion 564 septillion 39 sextillion 457 quintillion 584 quadrillion 7 trillion 913 billion 129 million 639 thousand 936

Its a very big number

10^(256*log(2)/log(10)) ≈ 10^77

Because of reflections and a few invalid keys at the very top, it is only about half that.

So closer to 57896044618658097711785492504343953926634992332820282019728792003956564819968

I wondered if i'd get away with not mentioning that lol

Way more than the number of atoms in the universe.

I’d estimate something like (26+26+10)^length of key, which is like what, 64 characters? So ballpark (2^6)^64 which is like 2^384 or ballpark 10^100+