Replying to Avatar arkinox

If u by chance know how to generate geometry data for a goldberg polyhedron with a radius of 6371km where each face is ~76m across, HIT ME UP
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Mike Dilger ☑️ 2y ago

First off, you can't have "each face" be 76m across because some faces are hexagons and some faces are pentagons.

If you want each hexagon to have a given edge length, call that E, then the formula for the order of a goldberg polyhedron with radius 6371 is:

I = dont(fucking) * know / pi^2

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