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Replying to Avatar SatsAndSports

If X is rational, there will be at least one (actually, infinitely many) Ms for which MX is an integer, and therefore the cosine is either -1 or +1

M! includes many even numbers, therefore the cosine will be +1, not -1

For irrational X, the cosine is always strictly between -1 and +1, and therefore tends to zero as n increases

(I still suspect in missing something, no pen and paper at hand)

And now I'm curious about complex X too

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billybigpotatoes 1mo ago

The reason it cannot take a value of -1 is simply because its an even power of cos(x).

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