Replying to Avatar Jack K

Well for one, a UTXO being sent to a 2 of 2 lighting channel is 2 UTXOs, the funding one (destroyed) the channel balance (new). This funding UTXO exists in the past and influences the new UTXO (via intention). And the state of the UTXO is even less certain as now transactions can occur between the two peer to peer parties without wanting to resolve uncertainty (A quantum bit transacting states between two parties without settling certainty). Measuring in quantum mechanics forcefully collapses the state, bitcoin it does not; it cannot without valid signature. This is non-local. Past information interacting with the present, the interaction is instantaneous (when the block is mined). It fundamentally inviolates bell inequality; Bitcoin is non-local.

The location and state of all UTXOs is known and deterministic for every block, even when UTXOs are spend and destroyed, their state is still preserved in time forever and directly influence the new UTXO. Yet the new UTXO also maintains its quantum nature, stored classically-quantum behavior.

Bitcoin is the quantum-classical computer that computes the most important thing for us; a peer to peer electronic (energy) cash system. Conservation of energy in the human energy domain allows use as humans to perform the computation of meaning for our UTXOs (qubits). No single owner of the qubits l, No single computer storing the data, no single centralized observer, opt in consensus. Physics is all about consensus, right? Our decisions are computed on bitcoin and preserved forever.

Interesting perspective with lightning channels, but something in the past affecting something in the future does not mean entanglement.

Are you able to provide a proof instead of just words? I do not see how a mined block violates a bell inequality, again do you have a proof?

It is not easy to show whether an arbitrary quantum state is entangled or not, but if you could describe a protocol for generating a bell state using two UTXOs that would be very interesting. If you can not generate a certain state, what decoherence is solved? You have no quantum-information on the state, so there is no quantum information to be lost.

Anyways, I am signing of social media till next saturday. Thanks for taking time to respond.

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