(a + b)^2 = (a - b)^2 + 4ab
Discuss
#math #the_mechanics_of_proof
(a + b)^2 = (a - b)^2 + 4ab
Discuss
#math #the_mechanics_of_proof
0 = 0 ?
I suck at maff. 🙈
Did you want me to write it out in a proof? I'm just guessing that the two parenthesis-bits cancel each other out and you end up with 0=4ab and that means one of the elements in 4ab must also be 0.
But, I'm sort of mathematically illiterate. Probably some trick I'm overseeing or something.
No, I was just trolling for engagement.
MUHAHAHA YOU FEEL INTO MY TRAP!

LOL
But... am I right?
Yes. If you factor them out and combine terms on both sides they are the same.
i forgot everything
They are equal:
1. (a + b)^2 = (a - b)^2 + 4ab
2. a^2 + 2ab + b^2 = a ^ 2 - 2ab + b^2 + 4ab
3. The right side simplifies to: a ^ 2 + 2ab + b^2
I've been reading: https://hrmacbeth.github.io/math2001/