nostr:npub1nadtggdgf58wx4jjyu7x0ajkx94h873syn8mlt5jnmqgl600texsk42adz ... but the answer is now found, the Moon's diameter is a thousand times bigger ... 3475 km, not 3475 m.

So it's 3.34 times 1000 seconds, or about 56 minutes.

nostr:npub16rumu76wqz4u00e9swtenuf4c9tlvx2p6vm7trdmaduky2kayshscjm0h5 Yup.

Thanks.

nostr:npub1jwllprty3r83mu06vka8drp059s8hmn4fa766eje62jeygayelnsq05rwk Yup ... exactly right.

Now editing the original to admit the gaffe.

nostr:npub1yzgcvpqkhc8zq7y4gx9v9ch8syk53xcsetw52l8mh3l7nup2gktqux3zfx Hah !!!

There we go, so the answer is about 1000 time bigger.

That makes sense !!!

Thank you ... feeling embarrassed now ...

nostr:npub1nadtggdgf58wx4jjyu7x0ajkx94h873syn8mlt5jnmqgl600texsk42adz Close to the horizon there are atmospheric effects that screw with the numbers, so while I agree with your intuition, your evidence is not as convincing as you might hope.

nostr:npub1h26g0vlvpxmqts4kykaaluwnq23x8fwc66t76vhvpmwdtaummzlsnkdd84 Completely clouded out here.

8-(

Distance to the Moon is about 390 Megameters, time to orbit is 27.32 days, so speed in m/s is:

D*2*pi/T/86400 ~ 1040 m/s

Diameter is about 3500 m, so time of occlusion is:

3500/1040 ~ 3.36

More accurately, diameter ~ 3475m, hence

3475/1040 ~ 3.34.

Seems low to me.

Can someone check my answer:

Does the Moon travel it's own diameter in about 3.34 seconds?

(Relative to the Earth)

So if it passed directly in front of a star, does it only take 3.34 seconds for that star to reappear on the other side?

Working to follow ...

In about half an hour, #UK_ISS #ISS pass, starting at 21:22:15, duration 130 secs, bright, Magnitude -2.5

Documenting this so I can come back to it later:

Calling nostr:npub12tahzsgclh8rsuue5ks99ka5wpydp9nr3sq3865y8360dyzjxtps3fnf76 ...

nostr:npub19lt4284mghqxekzm6n5njxurnxrxhqhrva2leusdsuu5ja5jeycq66qfjk nostr:npub1lywey3rjuskr7kstpvwj3xafa56qrkfc6r7f665rxvw4sv2jw6ps5vruez

Some passes of the #ISS visible from the UK overnight - I'll post alerts closer to the time - #UK_ISS

Whiteboards are remarkable.

nostr:npub1lx750nj5lngjr4tvpynv5q3ujuw7tucmwz6w6wqxtsgmzzlu5thq5lejfr Super ... thanks.

Some passes of the #ISS visible from the UK overnight - I'll post alerts closer to the time - #UK_ISS

I recently decided to sell my vacuum cleaner - all it was doing was gathering dust. -- Tim Vine

nostr:npub15wp53f6vfvr88zwg8jep4evdpjwl6exxpzfd7uwgxp2rxszcgdts993a95 nostr:npub1cn9fsandgc6nfkdq8sqr9szh0x5djdce3pkgy8f6enxqnxwzx8ssax9nha Best explained with a picture, but can't do that now, so here's a description.

Take a square, mark the centre, cut out the triangle between the centre and the bottom edge. Glue that onto the right hand side to get an irregular hexagon that I think is vaguely an abstract cow.

Got that?

So the resulting shape, the cow, has a classical two piece dissection where the pieces can be assembled into a square. After all, that's how the cow was constructed.

So ...

Find a *different* two piece classical dissection of the cow where the pieces can be assembled into the square.

Do not give it away !!!

DM me if (or when!) you get a solution.

Someone at nostr:npub1cn9fsandgc6nfkdq8sqr9szh0x5djdce3pkgy8f6enxqnxwzx8ssax9nha solved the cow problem!

Simultaneously impressive, exciting, and depressing ...

#TMiP23

The biggest waste of time is to do well something that we need not do at all. -- Gretchen Rubin, 'Better Than Before'

nostr:npub1uhnx67vlf04mwtt7qrjyx47gpmtf3twz4nrfmx9lspw6rrv5gkhsv42f8t Nice one ...

I like all of Steve's videos, they're really good.

Q: What do you get when you cross a mosquito with a mountaineer? A: Nothing - you can't cross a vector with a scalar.