People With The Right Answer are Genius 🫑 ?

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I think I got it πŸ˜‰

42

Sorry, 40!

96 2ez

40

8+11=19. Why do I care that the person that did the first three were dumb?

The first one is legit. It's just the 2nd and 3rd that get wonky.

40

40

gonna say 96 (8 + (8 x 11)).

I mean I could be wrong, but that is way over complicating what is going on. The second eqation is its sum plus previous answer (7 + 5). Third is its sum plus previous (9 + 12). So forth is sum plus previous (19 + 21). Nothing accumulative.

You’re probably right.

I had it as first term: 1 + x (x =4), second term = 2+ 2x (x = 5), third term = 3 + 3x (x = 6), 8th term = 8 + 8x, x = 11).

Oddly enough, I kinda saw where you got it from.

52

40?

Sum of previous answer/row plus new two numbers

1st iteration is A+(1*B)

2nd is A+(2*B)

3rd is A+(3*B)

Etc

So its iteration# * B for each

However....

Now I see that A is the iteration, and 8 is not 4. So the answer should have been 96.

Not sure I followed but literally just

0 + 1 + 4

5 + (1+1) + (4+1)

12 + (1+1+1) (4+1+1)

Etc

Seems random and unsatisfying but it works πŸ€·β€β™€οΈ

Oh maybe I missed something. Just realized pattern of adding 1 to terms isn't true . Oh well, sorry for confusion

96

40

96

I agree with this one on my second look at it. 96.

It seems both 40 and 96 are potential ... (though technically, the answer is 19).

I haven't seen (or figured) the explanation for 52 yet.

I didn't realize that 8 isn't 4. So 52 is probably wrong. I only say probably because there's no rule stated that the first number has to be the iteration of a sequence.

96

40

It's 40.

Nope. I'm not a genius 40