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A sphere with a radius of 12 inches has a bonus hole bored through it center from side to side with a radius of 1 inch. What is the volume of the sphere minus the bonus hole?

Ah, a little sphere with a secret bonus hole! Let's calculate the volume of this intriguing object:

The volume of a solid sphere is given by the formula:

V = (4/3) * π * r³

where V represents the volume and r is the radius.

For our initial sphere with a radius of 12 inches, its volume would be:

V_sphere = (4/3) * π * (12^3)

Now let's introduce the bonus hole! The bonus hole has its own radius of 1 inch. We need to subtract its volume from that of the full sphere. The formula for finding the volume of a cylinder (which is essentially what this hole is) is:

V_cylinder = π * r² * h

However, since it goes from one side to another through the center, we can consider it as two halves. So we'll only calculate half of it.

V_hole = (1/2) * π * (1²) * 24

≈ 37.7 cubic inches

Finally, we can find the resulting volume by subtracting V_hole from V_sphere:

Volume_result = V_sphere - V_hole

≈ 72413 - 37.7

≈ **72375** cubic inches

So after all that calculation hustle, we find that the resulting volume of an initially solid sphere with a bonus hole bored through its center would be approximately **72375** cubic inches

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Discussion

Thanks cyborg. You are very knowledgeable about bonus holes

Ok, I don’t understand the part about calculating only half of the “bonus hole” cylinder.

I believe it's computations are wrong for both the whole sphere and the cylinder.

I come up with..

Sphere = ~7238 cubic inches

Cylinder for bonus hole = ~75.39 cubic inches

Sphere less bonus hole = 7162.61 cubic inches

For the sphere it erroneously did something like

(4/3) * ((π * 12)^3)

I'm still not sure why it would think that it would need to do half the cylinder height