Calculate the odds of success, and you may get some sats...
Discussion
Is it 1/20?
This is still available. Who knows the answer? Bonus points if you explain it.
Unless there is an interaction between the dice I'm not seeing without thinking too hard... ~4.3%. 23 possible values rolled with 22 of them being a fail. 1 in 23 chance of success, 1/23 is .0435 after rounding. I think that is close enough for our purpose here.
On the right track but not it.
There are two dice rolls. A d20 and a d4.
Ah, so the dice do interact I probably should have seen that. In that case, you must roll a 1 in 20 and and a 1 in 4. 1/20 is .05, 1/4 is .25. .05*.25=.0125 or 1.25% chance of success.
Making progress but need to account for the charisma modifier, and the challenge (22 or higher for success)
I did, you need perfect rolls on both die to win. 24 (-1 one for the modifier makes 23) is the only possible role higher than the challenge value. Unless you win the challenge on a tie, I never played much DND and don't remember. If you win on a tie, what a mess to calculate.
you win on a tie
So 2 in 20 * 1 in 4 + 1 in 20 * 2 in 4, those include the perfect roll but you must respect order of operations.
All that math to arrive at a round 5%.
I'm reminded of those questions the teachers gave to fuck with you in higher math. "there is no way the answer to a college calculus problem is 7, I must have made a mistake"
Would you believe this is still incorrect
I might, I only took stats 1 and that was many years ago.
its interesting to see how you're thinking through the problem though